Solution :
given that,
pressure of CO2=2.5atm
1 atm = 1.01325x 105 pa so that
pressure of CO2 = 2.5x1.01325x105pa
= 2.533125 x 105 pa
KH = 1.67 x 108 pa
ACcording to henry's law p= KH*X
or X=P/KH
= 2.533125 x 105/1.67x 108
= 1.52 x 10-3
But we have 500ML odf soda water so that
Volume of water = 500mL
Density of water =1g/ml
mass = volume x density
500 mL of water = 500g of water
molar mass f water (H2O) = 18g mol-1
number of moles =
mole fraction of liquid b = 1-0.30 = 0.70
Vapoure pressure of pure water (solvent) at 298 K, p0 = 23.8 mm
Vapour pressure of solution, p = ?
Mass of solvent ,W = 850 g
Mass of solute,M = 50 g
Mol. mass of water (H2O), M = 18 g mol–1
Mol.mass of urea NH2 CO NH2
= 14 + 2 + 12 + 16 + 14 + 2
= 60 g mol–1
According to Raoult's law,
Hence, 23.78 mm Hg. Ans.
It is given that the solubility of H2S in water at STP is 0.195m, i.e., 0.195 mol of H2S is dissolved in1000 g of water.
=
At STP pressure (P) = 0.987bar
According to henry's law p = kH x